z^2+4iz+12=0

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Solution for z^2+4iz+12=0 equation:


Simplifying
z2 + 4iz + 12 = 0

Reorder the terms:
12 + 4iz + z2 = 0

Solving
12 + 4iz + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 4iz + -12 + z2 = 0 + -12

Reorder the terms:
12 + -12 + 4iz + z2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 4iz + z2 = 0 + -12
4iz + z2 = 0 + -12

Combine like terms: 0 + -12 = -12
4iz + z2 = -12

Add '-1z2' to each side of the equation.
4iz + z2 + -1z2 = -12 + -1z2

Combine like terms: z2 + -1z2 = 0
4iz + 0 = -12 + -1z2
4iz = -12 + -1z2

Divide each side by '4z'.
i = -3z-1 + -0.25z

Simplifying
i = -3z-1 + -0.25z

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